PhP - Encontrar erro de sintaxe

Olá pessoal,

Gostaria de saber se há algum erro de sintaxe nesse código:

mysql_query("UPDATE $property_table SET
propertyoption = " . $sql->quote ( $cgi->getValue ( "propertyoption" ) ) . ",
propertytype = " . $sql->quote ( $cgi->getValue ( "propertytype" ) ) . ",
propertyprice = " . $sql->quote ( $cgi->getValue ( "propertyprice" ) ) . ",
propertybedrooms = " . $sql->quote ( $cgi->getValue ( "propertybedrooms" ) ) . ",
propertybathrooms = " . $sql->quote ( $cgi->getValue ( "propertybathrooms" ) ) . ",
propertyyearbuilt = " . $sql->quote ( $cgi->getValue ( "propertyyearbuilt" ) ) . ",
propertylivingarea = " . $sql->quote ( $cgi->getValue ( "propertylivingarea" ) ) . ",
propertyplotsize = " . $sql->quote ( $cgi->getValue ( "propertyplotsize" ) ) . ",
propertyaddress = " . $sql->quote ( $cgi->getValue ( "propertyaddress" ) ) . ",
propertylocation = " . $sql->quote ( $cgi->getValue ( "propertylocation" ) ) . ",
propertypostcode = " . $sql->quote ( $cgi->getValue ( "propertypostcode" ) ) . ",
shortdescription = " . $sql->quote ( $cgi->getValue ( "shortdescription" ) ) . ",
longdescription = " . $sql->quote ( $cgi->getValue ( "longdescription" ) ) . ",
propertystatus = " . $sql->quote ( $cgi->getValue ( "propertystatus" ) ) . ",
propertyshow = " . $sql->quote ( $cgi->getValue ( "propertyshow" ) ) . ",
featuredproperty = " . $sql->quote ( $cgi->getValue ( "featuredproperty" ) ) . ",
virtualtour = " . $sql->quote ( $cgi->getValue ( "virtualtour" ) ) . ",
propertyowner = " . $sql->quote ( $cgi->getValue ( "propertyowner" ) ) . "

WHERE id = '$_POST[id]'") or die ("$DatabaseError2");

Obrigado a todos!