[Resolvido] [Código] Converter números para texto em C+

Olá!

Bom... estava fazendo um exercício de um livro meu, que estou lendo para aprimorar meus conhecimentos, e me deparei com um probleminha que me deu muita dor de cabeça... se alguém estiver com dúvidas quanto a isso, é só dar uma checada ;D

PS: O programa não faz a checagem para ver se são só números ou se há caracteres inválidos... Sinta-se livre para adicionar caso queira. Só peço para postar aqui depois xD

Aqui a questão do livro:

Write a program that converts numbers to words. Example: 895 results in "eight nine five."

Abaixo o código:

convert-numbers-to-text.cpp

/********************************************************
convert-numbers-to-text -- program to convert
numbers to words.

Author: LordEvil

Purpose: Exercise of a book

License: GNU GPL v3

Usage:
Run the program, do what the program say to do.
********************************************************/

#include <iostream>
#include <string>

int main()
{
// >>>>>>>>>>>> Local variable declaration <<<<<<<<<<<<<<<< \\
std::string input_from_console; // Number that will be input by stdin
register int iterator = 0; // Iterator for loops...

// Starts the while loop for inputting
while(true)
{

// >>>>>>>>>>>> Gets the value to calculate <<<<<<<<<<<<<<<< \\

	std::cout << "Please type one number (type 0 to exit): ";
	std::getline(std::cin, input_from_console);

	// >>>>>>>>>>>> Calculates the value <<<<<<<<<<<<<<<< \\

	// Uses the algorithim and calculates:

	// If is 0, or wasn't input any value, exits:
	if( !input_from_console.size() || (input_from_console.size() == 1 && input_from_console.at(0) == '0') )
 break;

	// Loop continue while input_from_console has characters.
	for(iterator = 0; (unsigned) iterator < input_from_console.size(); ++iterator)
	{
 // Prints the characters
 switch( input_from_console.at(iterator) )
 {
 case '-':
 // If is this character, couts the equivalent of it in letters...
 std::cout << " Minus ";
 break;

 case '0':
 // If is this number, couts the equivalent of it in letters...
 std::cout << " Zero ";
 break;

 case '1':
 // If is this number, couts the equivalent of it in letters...
 std::cout << " One ";
 break;

 case '2':
 // If is this number, couts the equivalent of it in letters...
 std::cout << " Two ";
 break;

 case '3':
 // If is this number, couts the equivalent of it in letters...
 std::cout << " Three ";
 break;

 case '4':
 // If is this number, couts the equivalent of it in letters...
 std::cout << " Four ";
 break;

 case '5':
 // If is this number, couts the equivalent of it in letters...
 std::cout << " Five ";
 break;

 case '6':
 // If is this number, couts the equivalent of it in letters...
 std::cout << " Six ";
 break;

 case '7':
 // If is this number, couts the equivalent of it in letters...
 std::cout << " Seven ";
 break;

 case '8':
 // If is this number, couts the equivalent of it in letters...
 std::cout << " Eight ";
 break;

 case '9':
 // If is this number, couts the equivalent of it in letters...
 std::cout << " Nine ";
 break;

 default:
 // Wow, strange error...
 std::cout << " Value Invalid! ";
 break;
 }
	}

	std::cout << "\n\n";
}

return 0;
}

Abraços :D