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[Resolvido] Alteração de código

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Tenho um código com efeito marquee contínuo, porém ele só atua verticalmente para cima e não manjo muito JS, queria saber como alterar esse código para fazer o efeito ir para a ESQUERDA:

 

<script type="text/javascript">
/*
Cross browser Marquee II- © Dynamic Drive (www.dynamicdrive.com)
For full source code, 100's more DHTML scripts, and TOS, visit http://www.dynamicdrive.com
Modified by jscheuer1 for continuous content. Credit MUST stay intact for use
*/

//Specify the marquee's width (in pixels)
var marqueewidth="200px"
//Specify the marquee's height
var marqueeheight="150px"
//Specify the marquee's marquee speed (larger is faster 1-10)
var marqueespeed=1
//Specify initial pause before scrolling in milliseconds
var initPause=1000
//Specify start with Full(1)or Empty(0) Marquee
var full=1
//Pause marquee onMousever (0=no. 1=yes)?
var pauseit=1
//Specify Break characters for IE as the two iterations
//of the marquee, if text, will be too close together in IE
var iebreak='<p></p>'

//Specify the marquee's content
//Keep all content on ONE line, and backslash any single quotations (ie: that\'s great):

var marqueecontent='<font face="Verdana">Thank you for visiting <a href="http://www.dynamicdrive.com">Dynamic Drive.</a></p><p>If you find this script useful, please consider linking to us by <a href="../link.htm">clicking here.</a></p><p>Visit our partner <a href="http://javascriptkit.com">JavaScript Kit</a> for JavaScript tutorials.</font></p>'


////NO NEED TO EDIT BELOW THIS LINE////////////
var copyspeed=marqueespeed
var pausespeed=(pauseit==0)? copyspeed: 0
var iedom=document.all||document.getElementById
var actualheight=''
var cross_marquee, cross_marquee2, ns_marquee

function populate(){
if (iedom){
var lb=document.getElementById&&!document.all? '' : iebreak
cross_marquee=document.getElementById? document.getElementById("iemarquee") : document.all.iemarquee
cross_marquee2=document.getElementById? document.getElementById("iemarquee2") : document.all.iemarquee2
cross_marquee.style.top=(full==1)? '8px' : parseInt(marqueeheight)+8+"px"
cross_marquee2.innerHTML=cross_marquee.innerHTML=marqueecontent+lb
actualheight=cross_marquee.offsetHeight
cross_marquee2.style.top=(parseInt(cross_marquee.style.top)+actualheight+8)+"px" //indicates following #1
}
else if (document.layers){
ns_marquee=document.ns_marquee.document.ns_marquee2
ns_marquee.top=parseInt(marqueeheight)+8
ns_marquee.document.write(marqueecontent)
ns_marquee.document.close()
actualheight=ns_marquee.document.height
}
setTimeout('lefttime=setInterval("scrollmarquee()",20)',initPause)
}
window.onload=populate

function scrollmarquee(){

if (iedom){
if (parseInt(cross_marquee.style.top)<(actualheight*(-1)+8))
cross_marquee.style.top=(parseInt(cross_marquee2.style.top)+actualheight+8)+"px"
if (parseInt(cross_marquee2.style.top)<(actualheight*(-1)+8))
cross_marquee2.style.top=(parseInt(cross_marquee.style.top)+actualheight+8)+"px"
cross_marquee2.style.top=parseInt(cross_marquee2.style.top)-copyspeed+"px"
cross_marquee.style.top=parseInt(cross_marquee.style.top)-copyspeed+"px"
}

else if (document.layers){
if (ns_marquee.top>(actualheight*(-1)+8))
ns_marquee.top-=copyspeed
else
ns_marquee.top=parseInt(marqueeheight)+8
}
}

if (iedom||document.layers){
with (document){
if (iedom){
write('<div style="position:relative;width:'+marqueewidth+';height:'+marqueeheight+';overflow:hidden" onMouseover="copyspeed=pausespeed" onMouseout="copyspeed=marqueespeed">')
write('<div id="iemarquee" style="position:absolute;left:0px;top:0px;width:100%;">')
write('</div><div id="iemarquee2" style="position:absolute;left:0px;top:0px;width:100%;z-index:100;background:white;">')
write('</div></div>')

}
else if (document.layers){
write('<ilayer width='+marqueewidth+' height='+marqueeheight+' name="ns_marquee">')
write('<layer name="ns_marquee2" width='+marqueewidth+' height='+marqueeheight+' left=0 top=0 onMouseover="copyspeed=pausespeed" onMouseout="copyspeed=marqueespeed"></layer>')
write('</ilayer>')
}
}
}
</script>

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Acho que seria bom você dizer como resolveu isso, para que possa ajudar pessoas com a mesma dúvida.

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